Globalus minimumas

\begin{eqnarray}f(x_A) \le f(x)\ x \in A,
\end{eqnarray}


arba

\begin{eqnarray}x_A = \arg \min_A f(x),
\end{eqnarray}


kur $A$ leistina sritis.


jonas mockus 2004-03-01