Pavyzdzio sprendinys

\begin{eqnarray}u^*=U=p_1 p_2/(p_1+p_2) , \nonumber \\
v^*=V=p_1+p_2-2p_1p_2/(p_1+p_2) .
\end{eqnarray}


Kai $p_1=1/3, p_2=2/3$

\begin{eqnarray}x1^*=y_1^*=2/3,\ x_2^*=y_2*=1/3,\ u^*=2/9,\ v^*=5/9
.
\end{eqnarray}


Bendresniu atveju

\begin{eqnarray}y_i=x_i= \prod_{k \neq i}p_k /(\sum_i \prod_{k \neq i} p_k) ,\\
\end{eqnarray}


kur $\prod_{k \neq i} p_k$ tai sandauga visu $p_k$ iškyrus $p_i$.



jonas mockus 2004-03-01